0=x^2-150x+635

Solution for 0=x^2-150x+635 equation:

0=x^2-150x+635

We move all terms to the left:

0-(x^2-150x+635)=0

We add all the numbers together, and all the variables

-(x^2-150x+635)=0

We get rid of parentheses

-x^2+150x-635=0

We add all the numbers together, and all the variables

-1x^2+150x-635=0

a = -1; b = 150; c = -635;
Δ = b2-4ac
Δ = 1502-4·(-1)·(-635)
Δ = 19960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19960}=\sqrt{4*4990}=\sqrt{4}*\sqrt{4990}=2\sqrt{4990}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-2\sqrt{4990}}{2*-1}=\frac{-150-2\sqrt{4990}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+2\sqrt{4990}}{2*-1}=\frac{-150+2\sqrt{4990}}{-2}
$